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shawnbart35
5th July 2007, 07:44 PM
Ive differentiated and my answer is 0.54 but when l drew the graph to find the gradient my answer was 0.44 .Is this okay for the problem below plz can someone check for me.

I = 2 (1 - e to the power of -2t)

The graph range is t=0 and 4 insteps of 0.2 secs

The gradient is to be found for t=1 between t=1 and 1.2

Im not quite sure on finding the gradient on the graph can someone plz help.Thanx

jamie
6th July 2007, 07:02 PM
you say gradient for t = 1 between t = 1 and 1.2

at what point do you require a gradient for 1 I think

shawnbart35
7th July 2007, 11:15 AM
yes pliz determine the gradient at t = 1

jamie
9th July 2007, 10:44 PM
I get the same answer as you 0.54 so the 0.44 is wrong im interested to know how you measured the gradient from a graph.

shawnbart35
10th July 2007, 12:09 PM
lve just looked at the problem again and it seems lve done the gradient calculation the wrong way to get the 0.44 so lm back to square one with this one but lm working on it right , anyone with an idea pliz feel free to help.Thanx

jamie
10th July 2007, 02:45 PM
grad = 0.54