Impossible question

[Pat_1211]

Im revising for my GCSE exams and trying to do papers now.

This problem is difficult. I don't know where to start.

A right angled triangle has sides x+1, 2x and 3x-1. Find x.

[MathsMan]

x+1, 2x and 3x-1. Find x.

Use Pythagoras' theorem
(3x-1) = (2x)+(x+1)
9x-6x+1 = 4x + x + 2x +1
4x-8x=0
4x(x-2)=0
x=0 or x=2

clearly x=2 (3,4,5 triangle)