Straight line question

[JoJo]

Can someone please tell me how to do this.

A line L has the equation y=2x-3. Find the equation of the line which is parallel to L and passes through the point (1,5).

[Delta]

Any lne has the form y=mx+c where m is the gradient.

For y=2x-3, the gradient m=2 so a line which is parallel must have the equation y=2x+c. Since the line you need to find passes through (1,5) then when x=1 y=5. Sub this into y=2x+c to give
5=2(1)+c
5=2+c
c=3
So the equation is y=2x+3

[JoJo]

I see where I was going wrong now.