C2 powers question

[Cannon]

How do i find x

2^(x+1) = 3^x

Thanks in advance.

[RTagger]

Need to use logs:

log2^(x+1) = log3^x

(x+1)log2 = xlog3

(x+1)/x = log3/log2 = 1.585

x+1 = 0.585x

1 = 1.585x - 1x = 0.585x

1 = 0.585x

x = 1.71

[Cannon]

Thankyou for that

[Rtagger]

No problem.