Help please ......

[Complex]

Can anyone help me.

Prove algebraically that the sum of two consecutive square numbers is an odd number.

[CoolerShaker]

Let the first number be n^2 and the next (n+1)^2

so n^2 + (n+1)^2 = n^2 + n^2 +2n + 1
= 2n^2 + 2n +1
= 2(n^2 +1) + 1

Since n^2+1 is multiplied by 2 it must be even.
Adding 1 to this term makes it odd.