Probability question

[DelBoy]

The events A and B have P(A) = 0.2, P(B) = 0.5 and P(AUB) = 0.6 Find:
(a) P(AnB) (b) P(A|B)

Thanks

[IceMan]

Use the identity P(AUB)=P(A)+P(B)-P(AnB) to work out (a)

0.6 = 0.2 + 0.5 - P(AnB)
=> P(AnB) = 0.7 - 0.6
=> P(AnB) = 0.1

b) P(A|B) = P(AnB)/P(B)
= 0.1 / 0.5
= 0.2