Need Help in Geometer please ...

[poltergeist]

Hi,

Nearly broke my head on this ... Can anybody please help ???


Diameter of a table is fifteen times the diameter of a saucer. Saucers are to be placed such that they neither overlap each other nor the edge of the table. Whats the maximum count that you can get ?????? :eek:

[kenboon90]

by assuming de diameter of table is 30metre,juz assume!

den we can get de radius/diameter of saucer,den we find de area of both

den we'll get de ratio,done~

[StuartS]

This question is much more complex than your answer suggests. There are more rows that need to be taken into account and as the chord length decreases the question becomes more challenging.

[StuartS]

By laying out 1 p coins the problem can be reduced to a more visual form.

The diameter will consist of 15 coins

Think of this as being one at the centre and 7 on each side of the centre coin.

So you have a 7, 1, 7 pattern

Now start to consider the 1st row above this by laying the coins in between these to form a 7, 7 pattern = 14 coins

building upwards on the 2nd row. You get 6, 1, 6 = 13 coins

the 3rd row 7, 7 = 14 coins

the 4th row 6, 1, 6 = 13 coins

the 5th row 6,1,6 = 13 coins

the 6th row 5, 5 = 10 coins

the 7th row 4, 1, 4 = 9 coins

the 8th row 1, 1 = 2 coins

So in total for rows 1 to 8 the total is 14 + 13 + 13 + 10 + 9 +2 = 61

Now double this for the same pattern below the diameter. That brings the total to 122.

Finally add the 15 coins along the diameter to give a total of 137.

Most of my working which is far too lengthy to give here but involves the radius of the table being 7.5d where d is the diameter of a saucer and using various Pythag. and trig calculations.

I hope that helps in some way.

[kenboon90]

Hi,

Nearly broke my head on this ... Can anybody please help ???


Diameter of a table is fifteen times the diameter of a saucer. Saucers are to be placed such that they neither overlap each other nor the edge of the table. Whats the maximum count that you can get ?????? :eek:

mine correct o not plz help me check ya stuartS,appreciate ur help
=D

assume de diameter of table is 30m
den find its area

(pie)r² =225pie

den for saucer,its area is

(pie)1² =pie

den 225pie/pie=225

hence 225 saucers can b placed on de table

??

[kenboon90]

owh..nvm i know wat's wrong wif me dy ==

soli ya
haha

[StuartS]

Your answer assumes that there are no gaps and the saucers can be moulded to fill the gaps.

[poltergeist]

All of u got it Wrong :-) ... The answer is 187 .. The basic idea is to build concentric hexagon containing 1,6,12,18,24,30,36 and 32 circles .. Now you have to find all the gaps and fill those too with saucers .. horrible .. I got the solution description cant make anything out of it .. :-) .. cant upload it here too as its to much size .. :-(

[kenboon90]

All of u got it Wrong :-) ... The answer is 187 .. The basic idea is to build concentric hexagon containing 1,6,12,18,24,30,36 and 32 circles .. Now you have to find all the gaps and fill those too with saucers .. horrible .. I got the solution description cant make anything out of it .. :-) .. cant upload it here too as its to much size .. :-(

StuartS yea i knew my mistake ><

err poltergeist can u upload it to anywhere n den gime de link of de solution??