differentiation with x in index

[Unregistered]

how do you solve y= 2^x + 2^-x
please help

[Beeky]

I think u mean differentiate
y= 2^x + 2^-x

The differential of a^x with respect to x is (a^x)lna

therefore dy/dx = (2^x) ln 2 - (2^-x) ln 2