Variable acceleration - Help plz!

[Hulk]

If a =3s+5 and initially v=1 m/s when s=1 m, find v when s = 2 m.

I just can't get started.

[DigbyIsCool]

vdv/ds = 3s+5
integrate both sides
∫vdv =∫(3s+5) ds

v/2 = 3s/2 +5s +C

but v=1 m/s when s = 1m

½ = 3/2 + 5 +C
C=-6

v/2 = 3s/2 +5s -6
when s = 2m
v/2 = 3(4)/2 +5(2) -6
v= 20
v=2√(5) m/s