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snapper
6th September 2007, 02:48 PM
Can anyone show me how to factorise am-bm-an+bn

Thanks

KatieB
6th September 2007, 11:59 PM
am-bm-an+bn

Use factorising by grouping. Just look at the first two terms and pull out a common factor of m then the last two terms and pull out a common factor of -n

so am-bm-an+bn ≡ m(a-b) - n(a-b)

now (a-b) is a common factor to both terms so pull this out.

so am-bm-an+bn ≡ m(a-b) - n(a-b)
≡(a-b)(m-n)